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5/6x^2-12=18
We move all terms to the left:
5/6x^2-12-(18)=0
Domain of the equation: 6x^2!=0We add all the numbers together, and all the variables
x^2!=0/6
x^2!=√0
x!=0
x∈R
5/6x^2-30=0
We multiply all the terms by the denominator
-30*6x^2+5=0
Wy multiply elements
-180x^2+5=0
a = -180; b = 0; c = +5;
Δ = b2-4ac
Δ = 02-4·(-180)·5
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*-180}=\frac{-60}{-360} =1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*-180}=\frac{60}{-360} =-1/6 $
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